From post: 156883, Topic: tid=10464, author=-splosives- wrote:From post: 156874, Topic: tid=10464, author=Triton83 wrote:
Don't forget the shot time ! The period is not C but (C+t) with t = shot time (cf post #1 and #15 in this thread)
C = 60000/RPM - t
Then your equation will be :
RPM x (Y - ((Y x 60000 x a / RPM) - t)) = Damage done per minute
Maybe S can be a coefficient and not a fraction of yield as in
Damage/min = RPM x Y x S = RPM x Y x a(t+C)
[Edited on 25/1/2013 by Triton83]
for 2 ships standing still, the period should be equal to C
C = 60000/ RPM, because C is independent of fire distance or fire time, as it calculates shots when fired, not when hit.
I would recommend removing the "shot time" from calculations because it makes things even more complicated, and it's not really necessary to get an idea of DPS.
RPM x Y x (60000 x a / RPM) would be reasonable, but the meaning of "a" wouldn't be the same as in my calculation.
When I say fire time I mean the time took by cannon to produce shots, not the flying time of the projectiles
Let's figure it in numbers ! As you said before, we can consider this :
f = 1 / T where frequency is the RPM and T the period in minute.
We want a period in milliseconds so : f = 60000 x 1/ T
If you consider the shot is immediate (i.e. takes 0 ms), the period T would match C as you said. Here are 2 examples picked up in the weapon lab :
- 430 RPM correspond with 10C. If you apply the formula : f = 60000/10 = 6000 RPM
- 360 RPM correspond with 20C. Let's test it : 60000 x 1/20 = 3000 RPM
The RPM don't match ! So there is missing something in the period.
That's why I think that each shot takes some time to be shot. Let's say t is the shot time, then (C+t) would be the period.
if it is the case, we should have :
f = 1/T then f x T = 1
That's why I can say :
RPM x (C+t) = 1 min
then RPM x (C+t) = 60000 ms
then RPM x C + RPM x t = 60000
then t = (60000 - C x RPM)/RPM
If I use my two examples datas I get :
With C = 10 and RPM = 430 : t = 129 ms
With C = 20 and RPM = 360 : t = 123 ms
The two results doesn't match because of the approximation on C. But this calculation prove there is ~125 ms after each "cycle rate time".
Maybe it's the cannon firing process, maybe something else, but I'm sure the real shooting period is very bigger than C.
[If we use frequencies to find out periods we'll have :
T = 60000/RPM
T = 60000/430 = 139.5 ms
Now T = C + t
then C + t = 139.5 ms
then t = 139.5 - 10 = 129.5 ms]
[Edited on 25/1/2013 by Triton83]
